MULTICALCI
AWS D1.1 · AISC 360 · effective throat method

Fillet Weld Size Calculator

Check a fillet weld leg size against shear, axial and bending load. Returns effective throat, weld area, combined stress, allowable stress and utilisation, plus the AWS D1.1 minimum leg size for the joint.

AWS D1.1 AISC 360 E70 – E90 Single · Double · Group

Check a fillet weld

Weld Geometry & Loading

Enter your values and select Calculate.

Fillet weld formula

A fillet weld is checked on its effective throat — the shortest distance from the weld root to the face. For a 45° equal-leg fillet that is 0.707 times the leg size. All stress is referred to that throat area, never to the leg.

a = 0.707 × w — effective throat, mm (45° fillet) Aw = a × Lw × n — throat area, mm² (n = 1 single, 2 double) τV = V × 1000 / Aw — direct shear stress, MPa σN = N × 1000 / Aw — axial stress on throat, MPa σM = M × 10⁶ / (Aw × Lw / 6) — bending stress on throat, MPa τtot = √( τV² + (σtot / √3)² ) — combined, von Mises basis τallow = 0.30 × FEXX — AWS D1.1 / AISC 360

w leg size (mm) · a effective throat (mm) · Lw weld length (mm) · n number of weld lines · V shear (kN) · N axial (kN) · M moment (kN·m) · FEXX electrode tensile strength (MPa)

Throat, not leg. Sizing a fillet on its leg size overstates capacity by about 41 %. The 0.707 factor is the single most common error in hand weld calculations. For unequal-leg fillets the throat must be derived from the actual geometry rather than this factor.

Worked example

A bracket is attached with an 8 mm double-sided fillet weld, 250 mm long each side, carrying 120 kN of direct shear. Electrode is E70XX.

Given
Leg size w
8 mm
Weld length Lw
250 mm
Configuration
Double sided (n = 2)
Shear V
120 kN
Electrode
E70XX → FEXX = 480 MPa
Step 1 — throat and area
a = 0.707 × 8
5.66 mm
Aw = 5.66 × 250 × 2
2 828 mm²
Step 2 — stress
τV = 120 000 / 2 828
42.43 MPa
σtot (no axial or moment)
0 MPa
τtot
42.43 MPa
Step 3 — capacity
τallow = 0.30 × 480
144 MPa
Utilisation = 42.43 / 144
29.5 %
AWS D1.1 minimum leg
5 mm — 8 mm leg is compliant
τ 42.43 MPa vs 144 MPa allowable · utilisation 29.5 % → weld adequate

The weld is lightly loaded at under 30 % utilisation. Reducing to a 6 mm leg would raise utilisation to about 39 %, still comfortable, and would cut weld metal volume by roughly 44 % since deposit volume scales with the square of the leg.

Units and input ranges

QuantitySymbolUnitAccepted range
Leg sizewmm or in> 0
Weld lengthLwmm or in> 0
Shear forceVkN, N or kip≥ 0
Axial forceNkN≥ 0
Bending momentMkN·m≥ 0
Electrode strengthFEXXMPa> 0
Effective throatammoutput
Throat areaAwmm²output
Combined stressτtotMPaoutput

Imperial inputs are converted before calculation: 1 in = 25.4 mm and 1 kip = 4.44822 kN. All internal work is done in SI.

Electrode strengths

ClassificationFEXX (MPa)Allowable 0.30·FEXX (MPa)
E70XX480144
E80XX550165
E90XX620186

AWS D1.1 minimum fillet leg size

Thicker part joinedMinimum leg (mm)
Up to 6 mm3
Over 6 to 12 mm5
Over 12 to 19 mm6
Over 19 mm8

Frequently asked questions

How is fillet weld throat thickness calculated?

For a standard 45° equal-leg fillet the effective throat is 0.707 × leg size, because the throat is the perpendicular distance from the root to the hypotenuse of a right isosceles triangle. An 8 mm leg gives a 5.66 mm throat. For a complete joint penetration butt weld the throat equals the plate thickness. For a partial penetration weld this calculator uses the greater of leg − 3 mm or 70 % of the leg.

What is the allowable stress for a fillet weld?

This calculator uses 0.30 × electrode tensile strength, the AWS D1.1 and AISC allowable shear stress on the effective throat area. For an E70 electrode at 480 MPa the allowable is 144 MPa. For E80 at 550 MPa it is 165 MPa, and for E90 at 620 MPa it is 186 MPa.

What is the minimum fillet weld size allowed?

AWS D1.1 sets a minimum leg size based on the thickness of the thicker part joined, to ensure the weld cools slowly enough to avoid cracking. This calculator applies 3 mm up to 6 mm material, 5 mm up to 12 mm, 6 mm up to 19 mm and 8 mm above that. The minimum is a fabrication requirement and applies even when the strength calculation permits a smaller weld.

How are shear and moment combined on a weld?

Direct shear produces a stress of V / Aw. Axial force and bending produce a normal stress on the throat. The two are combined using a von Mises style relationship in which the normal component is divided by √3 before being added in quadrature to the shear component. The result is compared against the allowable shear stress on the throat.

Should I use a single or double sided fillet weld?

A double-sided fillet doubles the effective weld area for the same leg size and length, halving the stress. It also balances the joint and reduces angular distortion from one-sided shrinkage. Single-sided welds are used where access is restricted, but they induce eccentricity and should not be used for joints carrying significant bending about the weld line.

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